Question

If a translation of (x, y) = (x + 6. y-10) is applied to figure

ABCD, what are the coordinates of D'?
0 (-5.-2)
O (1.-12)
O (4, -15)
0 (-9,-6)​

Answer 1

The answer is "(1, -12)"

Explanation:

In the given question some information is missing, that is the attachment of the graph, which can be attached as follows:

In the attached figure file, the quadrilateral ABCD vertices are (-3, 4), (3,4),(1,-2), and (-5,-2)

To find the coordinates of the D' the translation of (x, y) = (x + 6, y-10)

where point D=(-5, -2),

`\to x=x+6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=y-10\\\\\to x=-5+6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=-2-10 \\\\\to x=1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=-12`

So, the coordinates of D' is (1,-12).