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A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.37x10-2 kg/s. The density of the gasoline is 739 kg/m3, and the radius of the fuel line is 3.37x10-3 m. What is the speed at which gasoline moves through the fuel line

User Irfandar
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1 Answer

3 votes

Answer:

Speed v = 2.04 m/s

the speed at which gasoline moves through the fuel line is 2.04 m/s

Step-by-step explanation:

Given;

Mass transfer rate m = 5.37x10^-2 kg/s.

Density d = 739 kg/m3

radius of pipe r = 3.37x10^-3 m

We know that;

Density = mass/volume

Volume = mass/density

Volumetric flow rate V = mass transfer rate/density

V = m/d

V = 5.37x10^-2 kg/s ÷ 739 kg/m3

V = 0.00007266576454 m^3/s

V = 7.267 × 10^-5 m^3/s

V = cross sectional area × speed

V = Av

Area A = πr^2

V = πr^2 × v

v = V/πr^2

Substituting the given values;

v = 7.267 × 10^-5 m^3/s/(π×(3.37x10^-3 m)^2))

v = 0.203678639672 × 10 m/s

v = 2.04 m/s

the speed at which gasoline moves through the fuel line is 2.04 m/s

User Dauren
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