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A wire carries a current of 4 A travelling to the left (-x direction). It is placed in a constant magnetic field of magnitude 0.05 T, pointing upward ( z direction). a. If 25 cm of the wire is in the magnetic field, what is the force on the current

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Answer:

0.05 N

Step-by-step explanation:

Data provided in the question

The Wire carries a current of 4A to the left direction

The constant magnetic field of magnitude = 0.05 T

Pointing upward i.e Z direction

The wire is in the magnetic field = 25 cm

Based on the above information, the force on the current is


= Current * constant\ magnetic\ field\ of\ magnitude * magnetic\ field


= 4 * 0.05 * 0.25

= 0.05 N

The direction will be the negative Y direction

User Sameer Kashyap
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