Question

Between 11 P.M. and 8:45 A.M., the water level in a swimming pool decreased by 3/8 in. Assuming that the water level decreased at a constant rate, how much did the water level drop each hour?

Answer 1

the water level drop per hour is
`(1)/(26)\,\,(in)/(h) \approx 0.03846\,\,(in)/(h)`

Explanation:

Notice that in between 11 PM and 8:45 AM on the following day, there is a change in time equal to 9 hours and 45 minutes = 9.75 hours.

If the water level of the pool dropped by 3/8 of an inch, and the rate was constant, then the rate of level drop per hour is:

`((3)/(8) in)/(9.75\,h) =(1)/(26)\,\,(in)/(h) = 0.03846\,\,(in)/(h)`