Question

Cystic fibrosis is the most common lethal genetic disease among Caucasians. with cystic fibrosis produce a mutated chloride (Cl-) channel protein that results in abnormal ion and water transport across epithelia such as that lining the lung, often making it difficult to breathe. Cystic fibrosis is inherited in an autosomal recessive manner; individuals who are heterozygous for the cystic fibrosis allele are carriers but do not exhibit the disease. An individual who has the disease has children with an individual who does not have the disease and is not a carrier. What is the chance that their child will not have the disease

Answer 1

The chance that the child of an individual with cystic fibrosis and a partner who is not a carrier will not have the disease is 100%, as the child will inherit only one recessive CF gene and be a carrier without showing symptoms. Medical interventions have improved life expectancy for CF patients.

Step-by-step explanation:

Cystic fibrosis (CF) is an autosomal recessive genetic disease that affects various systems in the body, causing thick mucus production that obstructs organs like the lungs and pancreas. This condition is the result of a mutation in the CFTR gene. In the scenario where an individual with cystic fibrosis has children with a partner who neither has the disease nor is a carrier, the chance their child will not have the disease is 100%. This is because the affected individual can only pass on the recessive CF gene, while the partner with two normal alleles will always provide a normal allele. Since cystic fibrosis is an autosomal recessive condition, having only one copy of the mutated allele will not result in the disease; thus, their children will be carriers but will not exhibit the symptoms.

Advancements in medical interventions have helped extend the life expectancy of those with CF into middle adulthood. Nonetheless, it remains a serious condition that requires comprehensive medical care.

Answer 2

The correct answer would be - 100% chances that their child will not have the disease.

Step-by-step explanation:

Cystic fibrosis is one of the lethal diseases that inherited in an autosomal recessive manner. The Autosomal recessive pattern takes place when the defected gene present in the autosome chromosomes of an individual and only exhibits when both copies of recessive gene present.

The affected person must have two copies of the recessive allele - cc and the gamete he will produce will be - c only, however in the normal person, both copy of allele must be dominant - CC and will produce the gamete - C only.

Then from Punnett square :

C C (normal parent)

(affected parent) c Cc Cc

c Cc Cc

By this, it is established that in case all the offspring will have one copy of dominant and one copy of recessive gene which means 100% chances of carrier child.

Thus, the correct answer would be - 100% chances that their child will not have the disease.