Answer:
Explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so x1<2
log7 50=x2
7^x2=50
7^2=49<50 so x2>2
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
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