Question

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A circle is centered at J(3,3) and has a radius of 12.

Where does the point F(-6, -5) lie?

Choose 1 answer:

Answer 1

Answer:outside the circle

Step-by-step explanation:i got it right

Answer 2

Explanation:

The equation of this circle is (x - 3)^2 + (y - 3)^2 = 12^2.

Let's substitute the coordinates of the given point and compare the results to the above equation: do they produce a correct statement?

(-6 - 3)^2 + (-5 - 3)^2 = ?

9^2 + 8^2 = 145

Because r = 12, the above result would need to be 144, not 145, if the given point were actually on the circle. We must conclude that (-6, -5) lies just outside the circle.

81 + 64 = 144