Question

Make P the subject of Pt²=2x-Pm a 2

Answer 1

`p = \frac {2x}{(2t^2 +m)}`

Explanation:

`p {t}^(2) = \frac {2x - pm}{2} \\ </p><p></p><p>2pt^2 = 2x - pm\\</p><p></p><p>2pt^2 +pm= 2x \\</p><p>p(2t^2 +m) =2x\\\\</p><p>\huge\purple {\boxed {p = \frac {2x}{(2t^2 +m)}}} </p><p> \\`