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Stereo speakers are manufactured with a probability of 0.100.10 being defective. TwentyTwenty speakers are randomly selected. Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.

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Answer:

The expected value of X is 2 with a standard deviation of 1.34.

Explanation:

For each speaker, there are only two possible outcomes. Either it is defective, or it is not. The probability of a speaker being defective is independent of other speakers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:


E(X) = np

The standard deviation of the binomial distribution is:


√(V(X)) = √(np(1-p))

Stereo speakers are manufactured with a probability of 0.1 of being defective

This means that
p = 0.1

Twenty speakers are randomly selected.

This means that
n = 20

Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.


E(X) = np = 20*0.1 = 2


√(V(X)) = √(np(1-p)) = √(20*0.1*0.9) = 1.34

The expected value of X is 2 with a standard deviation of 1.34.

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