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An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (constant) acceleration of the vehicle during this time? Group of answer choices

User Mi
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2 Answers

3 votes

Final answer:

To find the constant acceleration of a vehicle that changes its velocity from 40 m/s to 80 m/s over a distance of 200 m, one can use the kinematic equation v² = u² + 2as, which yields an acceleration of 12 m/s².

Step-by-step explanation:

To calculate the constant acceleration of a vehicle that changes its velocity from 40 m/s to 80 m/s over a distance of 200 m, we can use the following kinematic equation:

v² = u² + 2as

Where v is the final velocity (80 m/s), u is the initial velocity (40 m/s), a is the acceleration, and s is the distance over which the acceleration occurs (200 m)

Rearranging the formula to solve for a:
a = (v² - u²) / (2s)

Plug in the values:
a = (80² - 40²) / (2 × 200)

After calculation:
a = (6400 - 1600) / 400a = 4800 / 400a = 12 m/s²

Therefore, the constant acceleration of the vehicle is 12 m/s².

User Dsissitka
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6 votes

Answer:

Dear Kaleb

Answer to your query is provided below

Acceleration of the vehicle is 12m/s^2

Step-by-step explanation:

Explanation for the same is attached in image

An automobile moving along a straight track changes its velocity from 40 m/s to 80 m-example-1
User Null
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