Question

V=1/3Πr^2(2r+h)

PLEASE HELP!!!!!!!
Make h the subject of the formula
Need help ASAP...
PLEASE​

Answer 1

`h = \frac{3v - 2\pi \: r{ }^(3) }{\pi \: r {}^(2) }`

Explanation:

Step 1 add -2/3Πr^3 to both sides

v + -2/3Πr^3 = 1/3hpr^2 + 2/3Πr^3 + -2/3Πr^3

Step 2 divide both sides by (Πr^2)/3

(v + -2/3Πr^3)/(Πr^2)/3 = (1/3hΠr^2)/(Πr^2)/3

(3v - 2Πr^3)/Πr^2 = h

hope this helps....

Answer 2

h=
`(−2.094395r3+v)/(1.047198r2)`

Explanation:

v=(
`(1)/(3)` (3.141593))(r2)(2r+h)

Step 1: Flip the equation.

1.047198hr2+2.094395r3=v

Step 2: Add -2.094395r^3 to both sides.

1.047198hr2=−2.094395r3+v

Step 3: Divide both sides by 1.047198r^2.

h=
`(−2.094395r3+v)/(1.047198r2)`