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Evaluate the limit, or state that the limit does not exist.(6n^2-2n)/(n^2+8)

User Aardvark
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Assuming the limit is taken as n approaches infinity, we have


\displaystyle\lim_(n\to\infty)(6n^2-2n)/(n^2+8)=\lim_(n\to\infty)\frac{6-\frac2n}{1+\frac8{n^2}}=\boxed6

because the rational terms in the numerator and denominator will vanish.

User Jayanga
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