Question

2. Wood smoke can be a source of carbon monoxide. Wood produces about 200 g of CO per kg of wood burned. Suppose you make a very large bonfire by burning 400 kg of wood per hour. Assume it is a clear night over rough terrain with the wind blowing at 2.4 m/s (as measured at 10 m). Assume the effective stack height is 6 m. A. What is the rate of CO production (Q) in g/s

Answer 1

The correct answer will be "22,222 g/sec"

Step-by-step explanation:

The given values are:

Speed of wing,

`V_{w_(o)}=2.4 \ m/s`

Stack's height (effective),

`H = 6 \ m`

Stack's height (measured),

`h = 10 \ m`

Wood's burning rate,

`r = 400 \ kg/hr`

Amount of produced CO,

`A=200 \ g`

Now,

On converting the unit of wood's burning rate, we get

⇒
`r=400 \ kg/hr`

⇒
`=(400* 10^3)/(60* 60)`

⇒
`= 111.11 \ g/sec`

So that,

The rate of CO production will be:

⇒
`Q=A* r`

On putting the estimated values, we get

⇒
`=(200)/(1000)* 111.11`

⇒
`=22.222 \ g/sec`