Question

Your electric drill rotates initially at 5.35 rad/s. You slide the speed control and cause the drill to undergo constant angular acceleration of 0.331 rad/s2 for 4.81 s. What is the drill's angular displacement during that time interval?

Answer 1

The angular displacement is
`\theta = 29.6 \ rad`

Step-by-step explanation:

From the question we are told that

The initial angular speed is
`w = 5.35 \ rad/s`

The angular acceleration is
`\alpha = 0.331 rad /s^2`

The time take is
`t = 4.81 \ s`

Generally the angular displacement is mathematically represented as

`\theta = w * t + (1)/(2) \alpha * t^2`

substituting values

`\theta = 5.35 * 4.81 + (1)/(2) * 0.331 * (4.81)^2`

`\theta = 29.6 \ rad`