Answer:
Length = 550 m
Width = 275 m
Area = 151,250 m2
Explanation:
One side of the farmland is bounded by the river, so the perimeter we will need to enclose is:
![Perimeter = Length + 2*Width = 1100\ m](https://img.qammunity.org/2021/formulas/mathematics/college/dlqbacxktk89ugvoiq1b3vrjhq060c0qs5.png)
And the area of the farmland is given by:
![Area = Length * Width](https://img.qammunity.org/2021/formulas/mathematics/high-school/9o4tiofgxnozy1qtatv0tflzmu60nkvn6z.png)
From the Perimeter equation, we have that:
![Length = 1100 - 2*Width](https://img.qammunity.org/2021/formulas/mathematics/college/qnpkk76jn81zb63whn30h2uqr4ua2l9hk5.png)
Using this in the area equation, we have:
![Area = (1100 - 2*Width) * Width](https://img.qammunity.org/2021/formulas/mathematics/college/9mmp5wlhii8i08d8vtb76kofnbh78clprn.png)
![Area = 1100*Width - 2*Width^2](https://img.qammunity.org/2021/formulas/mathematics/college/z6djmw9m1azd2kdgxcprx4w950gz68t5x3.png)
Now, to find the largest area, we need to find the vertex of this quadratic equation, and we can do that using the formula:
![Width = -b/2a](https://img.qammunity.org/2021/formulas/mathematics/college/nbq33zytsuq24wwjia0z4o9bjrry0ipflt.png)
![Width = -1100/(-4)](https://img.qammunity.org/2021/formulas/mathematics/college/spktubtdxmnws7dv76dulujaf14crkrejq.png)
![Width = 275\ m](https://img.qammunity.org/2021/formulas/mathematics/college/ysyzkyiuy9a1622skfm6xhc2j5j8q8h5a4.png)
This width will give the maximum area of the farmland. Now, finding the length and the maximum area:
![Length = 1100 - 2*Width = 1100 - 550 = 550\ m](https://img.qammunity.org/2021/formulas/mathematics/college/ar1sm24m60m120bo0gof7c4dmh16z36ham.png)
![Area = Length * Width = 550 * 275 = 151250\ m2](https://img.qammunity.org/2021/formulas/mathematics/college/khr1cx9hhu92tb4u8krxbolw3v8uy84b6s.png)