Answer:
The correct answer to the following question will be "No". The further explanation is given below.
Explanation:
Probability (Keeping the disease out of 1 contact)
=
![0.5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jm4zyx0amqrc6ywhqqxl8ow3mkqscmbjg3.png)
Probability (not keeping the disease out of 1 contact)
=
![1-0.5](https://img.qammunity.org/2021/formulas/mathematics/college/vytp4asldxmxfn18m4jseeyorkofqs8oz3.png)
=
![0.5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jm4zyx0amqrc6ywhqqxl8ow3mkqscmbjg3.png)
Now,
Probability (not keeping the disease out of 2 contact)
= Keeping the disease out of 1 contact × not keeping the disease out of 1 contact
On putting the estimated values, we get
=
![0.5* 0.5](https://img.qammunity.org/2021/formulas/mathematics/college/m9qj3jhyo0jko9qa944nerj8ppgfrm12kk.png)
=
![0.25](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1xoma73gpfunng6kzc69ymazvmg3ko8398.png)
So that,
Probability (Keeping the disease out of 2 contact)
=
![1-0.25](https://img.qammunity.org/2021/formulas/mathematics/college/wcmphdwa46vboxxnn2xyh3wyn0zu0b5ic1.png)
=
![0.75 \ i.e., 75 \ percent](https://img.qammunity.org/2021/formulas/mathematics/college/nu1ni05r9807gmyyv5fnqjzjgfd9y9mufe.png)
∴ Not 100%