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1 vote
Is the function even, odd or neither?

f(x) = |x| + 1



Your answer:


Even

Odd

Neither

User Jsv
by
8.5k points

2 Answers

3 votes
Answer: Even

Explanation
User Zmaster
by
9.3k points
1 vote

Answer: Even

Explanation:

This graph has been translated up by one unit but is still symmetrical about the y axis.

A simple proof would be to check if f(x) = f(-x). If it does, then it is even.

To check for an odd function, check if f(-x) = -f(x). If it does, then it is even.

To check for neither, f(-x) will not equal -f(x)

User Meugiwara
by
8.5k points

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