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4 votes
(Squreroot x+2)(squreoot x-2)=0

User FPGA
by
7.9k points

1 Answer

2 votes

Answer:


\boxed{ \ x = 2 \ or \ x = -2 \ }

Explanation:

I understand that you want to solve this equation


√(x+2)√(x-2)=0

<=>


√((x+2)(x-2))=0

<=>


(x+2)(x-2)=0

<=>

x = 2 or x = -2

hope this helps

if your question is
(√(x)+2)(√(x)-2) = 0

then this is
(√(x))^2-4 = 0\\<=> x = 4

User Lawrence
by
8.9k points

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