187k views
1 vote
The equation x2 − 9 = 0 has real solution(s).

User Duthen
by
5.6k points

2 Answers

4 votes

Answer:

The roots are real and unequal (3, -3)

Explanation:

x²-9=0

ax²+bx+c=0

Comparing we get,

a= 1

b= 0

c = -9

Determinant: b²-4ac

= 0² - 4(1)(-9)

= 36>0

D > 0

Therefore, the equation has real and unequal roots.

Algebraic identity:

x² - a² = (x-a)(x+a)

Using this identity

x²-9 = (x+3)(x-3)

Roots are 3 and -3 which are real and not equal to each other

Hope this answer helps you ..

User Weifeng
by
5.5k points
6 votes

Answer:

2 real solutions

User Bumpbump
by
5.4k points