Question

12.0 V car battery has a voltage drop of 3.4 V when the starter draws 93 A of current. What is the resistance of the starter? O 88 m2 84 mg O 80 m2

Answer 1

`R_s = 0.093 \Omega`

Step-by-step explanation:

Voltage of the car battery = 12.0 V

Voltage drop in the battery = 3.4 V

The remainder of the voltage is the starter voltage, that is:

Starter voltage = Initial battery voltage - voltage drop

Starter voltage = 12.0 - 3.4

Starter voltage,
`V_(s)` = 8.6 V

Current drawn by starter,
`I_s` = 93 A

According to Ohm's law:
`V_s = I_s R_s`

Starter Resistance,
`R_s` =
`V_s/I_s`

`R_s = 8.6/93\\R_s = 0.093 \Omega`