Question

In the first step of glycolysis, the given two reactions are coupled. reaction 1:reaction 2:glucose+Pi⟶glucose-6-phosphate+H2OATP+H2O⟶ADP+PiΔG=+13.8 kJ/molΔG=−30.5 kJ/mol Answer the four questions about the first step of glycolysis. Is reaction 1 spontaneous or nonspontaneous?

Answer 1

Answer: Reaction 1 is non spontaneous.

Step-by-step explanation:

According to Gibb's equation:

`\Delta G=\Delta H-T\Delta S`

`\Delta G` = Gibbs free energy

`\Delta H` = enthalpy change

`\Delta S` = entropy change

T = temperature in Kelvin

When
`\Delta G` = +ve, reaction is non spontaneous

`\Delta G`= -ve, reaction is spontaneous

`\Delta G`= 0, reaction is in equilibrium

For the given reaction 1:
`glucose+Pi\rightarrow glucose-6-phosphate+H_2O`
`\Delta G=+13.8kJ/mol`

As for the reaction 1 , the value of Gibbs free energy is positive and thus the reaction 1 is non spontaneous.