Question

Suppose a piston automatically adjusts to maintain a gas at a constant pressure of 13.00 atm . For the initial conditions, consider 0.05 mol of helium at a temperature of 220.00 K . This gas occupies a volume of 0.07 L under those conditions. What volume will the gas occupy if the number of moles is increased to 0.08 mol (n2) from the initial conditions

Answer 1

The final volume of the gas is 0.112 L

Step-by-step explanation:

Step 1: Data given

Pressure is constant at 13.00 atm

The initial number of moles = 0.05 moles

The temperature = 220.00 K

Initial volume = 0.07 L

The number of moles is increased to 0.08 moles

Step 2: Calculate the new volume

V1/ n1 = V2/n2

⇒with V1 = the initial volume of the gas = 0.07 L

⇒with n1 = the initial number of moles of gas = 0.05 moles

⇒with V2 = the final volume = TO BE DETERMINED

⇒with n2 = the final number of moles of gas = 0.08 moles

0.07 L / 0.05 moles = V2 / 0.08 moles

V2 = 0.07 L * 0.08 / 0.05 moles

V2 = 0.112 L

The final volume of the gas is 0.112 L