Question

What is the sum? 3k/k^2+k-7/4K

Answer 1

`(k^2+5k)/(4k^2)`

Explanation:

A suitable common denominator is 4k^2. (This eliminates the first and last choices.)

`(3k)/(k^2)+(k-7)/(4k)=(4(3k))/(4(k^2))+(k(k-7))/(k(4k))\\\\=(12k+k^2-7k)/(4k^2)=\boxed{(k^2+5k)/(4k^2)}`