Question

Brenda collected this data from an experiment.

For the line of fit h = 0.6t + 0.44, what is the residual of the data point at t = 11?

Answer 1

The residual of the data point h = 0.6t + 0.44, is h = 7.04.

Explanation:

Given the line of fit, h = 0.6t + 0.44, which Brenda collected from an experiment, at the point t = 11, the residual of the data point is obtained by replacing t with 11 in the given equation h = 0.6t + 0.44.

Doing this, we have

h = 0.6(11) + 0.44

h = 6.6 + 0.44

= 7.04

This is what we want to obtain.

Answer 2

7.04

Explanation:

To get the value of residual of the data point, we simply substitute 11 for t

The substitution equation is h = 0.6t + 0.44

Substituting 11, we have

h = 0.6(11) + 0.44

h = 6.6 + 0.44

h = 7.04