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Hi, Please i need help with this question. Workings would be deeply appreciated .

A straight line which passes through the point (3,-4) makes intercept 3k and -5k on the x and y axes respectively. Find the value of k​

Hi, Please i need help with this question. Workings would be deeply appreciated . A-example-1

1 Answer

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Answer:

k = ⅕

Explanation:

The slope-intercept equation for a straight line is

y = mx + b, where

m = the slope and

b = the y-intercept

Data:

(3,4) = a point on the line

(3k,0) = x-intercept

(0,-5k) = y-intercept

Calculations:

1. Slope

m = (y₂ - y₁)/(x₂ - x₁) = (-5k - 0)/(0 - 3k) = -5/(-3) = ⁵/₃

This makes the equation

y = ⁵/₃x - 5k

2. k

Insert the value of the known point: (3,4)

4 = (⁵/₃)(3) - 5k

4 = 5 - 5k

-1 = -5k

k =

The figure below shows your graph passing through (3,4) with intercepts 3k and -5k on the x- and y-axes respectively .

Hi, Please i need help with this question. Workings would be deeply appreciated . A-example-1
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