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Given right triangle ABC . To the nearest degree, find the measure of angle B. 20° 43° 47° 70°

1 Answer

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Answer:

The answer is "70°"

Explanation:

In the given question an attachment file is missing. so, the attachment file and its solution can be defined as follows:

Given:

ABC is the right triangle.

Find B=?

Solution:


\Rightarrow \sin \theta= (p)/(h)\\\\


\Rightarrow \sin B^(\circ)=(AB)/(AC)= (4.8)/(5.1)\\\\


\Rightarrow \sin B^(\circ)= .941


\Rightarrow B^(\circ)= \sin^(-1) (0.941)\\\\\bold{\sin^(-1) (0.941) = 70.2^(\circ)}\\\\\therefore \ \ \ \ \bold{B^(\circ) = 70^(\circ)}

Given right triangle ABC . To the nearest degree, find the measure of angle B. 20° 43° 47° 70°-example-1
User Franklin Stine
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