Answer:
Width = 4 units
Explanation:
Let us pose the width as w, and the length as l. If the length is 2 units greater than the width, consider the following;
![l = 2 + w,\\\\w = width,\\l = length](https://img.qammunity.org/2021/formulas/mathematics/high-school/jz2usb3mcm7piqbh02izmlzl9ahet3wa1z.png)
The area of this rectangle can be determined through length * width / l * w, and is given to be 24 square units. We can say l = 2 + w instead, solving for the width ( w );
![( 2 + w ) * w = 24,\\2w+w^2=24,\\\left(w-4\right)\left(w+6\right)=0,\\w = 4, w = - 6\\\\Solution - width = 4 units](https://img.qammunity.org/2021/formulas/mathematics/high-school/snzsmy7s0an7s11x5wwy2ij91py4hfijl7.png)
As the width couldn't be a negative value, we had to take the positive of 4 and - 6, which was 4 units.