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You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source

User Costales
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Complete Question

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.

Answer:

The distance is
z = 4707.6 \ m

Step-by-step explanation:

From the question we are told that

The is distance between the headlight is
d = 0.681 \ m

The wavelength is
\lambda = 549 \ nm = 549 *10^(-9) \ m

The pupil diameter is
D = 4.63 \ mm = 0.00463 \ m

Generally, we can mathematically evaluate the resolution of the eye as


\theta = (1.22 * \lambda )/(D)

substituting values


\theta = (1.22 * 549 *10^(-9) )/(0.00463)


\theta = (1.45 *10^(-4) )^o

Now according to SOHCAHTOA rule


sin \theta = ( d)/(z)

Where z is the distance at which the eye can discern the two head light

given that the angle is very small
sin \theta = \theta

=>
\theta = ( d)/(z)

substituting values


1.45*10^(-4) = ( 0.681)/(z)

=>
z = (0.681)/(1.45 *10^(-4))

=>
z = 4707.6 \ m

User Youddh
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