Question

A stock solution will be prepared by mixing the following chemicals together:

3.0 mL of 0.00200 M KSCN
10.0 mL of 0.200 M Fe(NO3)3
17.0 mL of 0.5 M HNO3

Determine the molar concentration of Fe(NO3)3 in the stock solution.

Answer 1

The molar concentration of Fe(NO3)3 in the stock solution is 0.067 M.

Step-by-step explanation:

To determine the molar concentration of Fe(NO3)3 in the stock solution, we can use the formula:
C1V1 = C2V2

Where C1 and V1 are the initial concentration and volume of the Fe(NO3)3 solution, and C2 and V2 are the final concentration and volume of the stock solution.

Plugging in the values, we get:
0.200 M * 10.0 mL = C2 * 30.0 mL

Simplifying this equation, we find that the molar concentration of Fe(NO3)3 in the stock solution is 0.067 M.

Answer 2

0.067M Fe(NO3)3

Step-by-step explanation:

A stock solution is a concentrated solution that is diluted to prepare the solutions that you will use.

The volume of the stock solution is 3.0mL + 10.0mL + 17.0mL= 30.0mL.

The ratio between volume of the aliquot (10.0mL) and total volume (30.0mL) is called dilution factor, that is: 30.0mL / 10.0mL = 3

That means the Fe(NO3)3 is diluted 3 times. That means the molar concentration of the stock solution is:

0.200M / 3 =

0.067M Fe(NO3)3