Question

A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?

Answer 1

The electric flux through the sphere is
`8.58 *10^(5) (Nm^2)/(C)`

Step-by-step explanation:

Given

`Radius,\ r = 0.03m\\Charge,\ q =7.6\µC`

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε
`= 8.8542 * 10^(-12)`

Substitute ε
`= 8.8542 * 10^(-12)` and
`q =7.6\µC`; The formula becomes

Ф =
`(7.6\µC)/(8.8542 * 10^(-12))`

Ф =
`(7.6 * 10^(-6))/(8.8542 * 10^(-12))`

Ф =
`(7.6)/(8.8542) *(10^(-6))/(10^(-12))`

Ф =
`(7.6)/(8.8542) *10^(12-6)}`

Ф =
`0.85834970974 *10^(12-6)}`

Ф =
`0.85834970974 *10^(6)}`

Ф =
`8.5834970974 *10^(5)}`

Ф =
`8.58 *10^(5) (Nm^2)/(C)`

Hence, the electric flux through the sphere is
`8.58 *10^(5) (Nm^2)/(C)`