Question

Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5 m above the ground. When you quickly turn off the nozzle, you hear the water striking the ground next to you for another 1.8 s. What is the water speed as it leaves the nozzle?

Answer 1

The speed of the water as it leaves the nozzle is
`u =9.7 \ m/s`

Step-by-step explanation:

From the question we are told that

The height of the nozzle above the ground is
`h = 1.5 \ m`

The time taken for the flow to stop is t = 1.8 s

According the second law of motion

`h = ut - (1)/(2) gt^2`

making the initial velocity the subject

`u = (h + 0.5gt^2)/(t)`

here
`g=9.8 \ m/s^2`

substituting value

`u = (1.5 + 0.5 * 9.8 * (1.8)^2)/(1.8)`

`u =9.7 \ m/s`