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What is the equation, in slope-intercept form, of the line that is perpendicular to the line =} (x-6) and passes through tho point (-2,-2)? y-4= y=-3x - 19 y=-x+ 10 y = fx-1 y = 2 x + 1
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1 vote
What is the equation, in slope-intercept form, of the line that is perpendicular to the line

=} (x-6) and passes through tho point (-2,-2)?
y-4=
y=-3x - 19
y=-x+ 10
y = fx-1
y = 2 x + 1

User Stephen Searles
by
5.7k points

1 Answer

3 votes

Answer: y=-x+ 10

Explanation:

User Korbes
by
5.9k points
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