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Davina accelerates a box across a smooth frictionless horizontal surface over a displacement of 18.0 m with a constant 25.0 N force angled at 23.0° below the horizontal. How much work does she do on the box? A. 176 J B. 414 J C. 450 J D. 511 J Group of answer choices

1 Answer

4 votes

Answer:

W = 414 J, correct is B

Step-by-step explanation:

Work is defined by

W = ∫ F .dx

where F is the force, x is the displacement and the point represents the dot product

this expression can also be written with the explicit scalar product

W = ∫ F dx cos θ

where is the angle between force and displacement

for this case as the force is constant

W = F x cos θ

calculate

W = 25.0 18.0 cos (-23)

W = 414 J

the correct answer is B

User Rohit Tagadiya
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