Question

Given area of a rectangle: 7x^2+57x+8
Find Perimeter:

Answer 1

Perimeter of the rectangle is 16x+18 units.

Explanation:

The area of rectangle is

`7x^2+57x+8`

First we have to find the factor form of above expression.

Splitting the middle term, we get

`7x^2+56x+x+8`

`7x(x+8)+1(x+8)`

`(x+8)(7x+1)`

Area of a rectangle is the product of its dimensions. It means dimensions of the rectangle are (x+8) and (7x+1).

Perimeter of a rectangle is

`Perimeter=2(l+b)`

`Perimeter=2[(x+8)+(7x+1)]`

`Perimeter=2[8x+9]`

`Perimeter=16x+18`

Therefore, the perimeter of the rectangle is 16x+18 units.