Question

When you take your 1900-kg car out for a spin, you go around a corner of radius 56 m with a speed of 14 m/s. The coefficient of static friction between the car and the road is 0.88. Part A Assuming your car doesn't skid, what is the force exerted on it by static friction

Answer 1

6,650 newtons

Step-by-step explanation:

The computation of the force exerted on it by static friction is shown below:

Data provided in the question

Mass of car = m = 1,900 kg

speed = v = 14 m/s

radius = r = 56 m

Let us assume friction force be f

And, the Coefficient of friction =
`\mu`= 0.88

As we know that

`f = (mv^2)/(r)`

`= (1,900 * 14^2)/(56)`

= 6,650 newtons

We simply applied the above formula so that the force exerted could come