Answer:
Explanation:
We would set up the hypothesis test.
For the null hypothesis,
p = 0.24
For the alternative hypothesis,
p ≠ 0.24
This is a two tailed test
Considering the population proportion, probability of success, p = 0.24
q = probability of failure = 1 - p
q = 1 - 0.24 = 0.76
Considering the sample,
Sample proportion, P = r/n
Where
r = 12
n = 52
P = 12/52 = 0.23
We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.23 - 0.24)/√(0.24 × 0.76)/52 = - 0.17
Recall, population proportion, P = 0.24
The difference between sample proportion and population proportion(p - P) is 0.24 - 0.23 = 0.01
Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.24 - 0.01 = 0.23
the p for the right tail is 0.24 + 0.01 = 0.25
These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area
From the normal distribution table, the area below the test z score in the left tail 0.43
We would double this area to include the area in the right tail of z = 0.17 Thus
p = 0.43 × 2 = 0.86
The level of significance is 5%
Since alpha, 0.05 < than the p value, 0.86, then we would fail to reject the null hypothesis. Therefore, at 5% significance level, this information does not imply that the color preference of all college students is different (either way) from that of the general population.