Answer:
0.8973
Explanation:
Relevant data provided in the question as per the question below:
Free throw shooting percentage = 0.906
Free throws = 6
At least = 5
Based on the above information, the probability is
Let us assume the X signifies the number of free throws
So, Then X ≈ Bin (n = 6, p = 0.906)

Now
The Required probability = P(X ≥ 5) = P(X = 5) + P(X = 6)

= 0.8973