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find the equation of the line passing through the point (0,1) which is perpendicular to the line y=-3/4x-3

User Shousper
by
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1 Answer

6 votes

Answer:

y =
(4)/(3) x + 1

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = -
(3)/(4) x - 3 ← is in slope- intercept form

with slope m = -
(3)/(4)

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(-(3)/(4) ) =
(4)/(3)

The line crosses the y- axis at (0, 1 ) ⇒ c = 1

y =
(4)/(3) x + 1 ← equation of perpendicular line

User Siyad
by
8.9k points

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