Question

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds)

Answer 1

5.449 x 10¹⁸ Hz

Step-by-step explanation:

Energy (E) =Frequency (F) x Plancks constant (h)

F= 3.611x10⁻¹⁵J / 6.626 x 10⁻³⁴ Js⁻¹

F =5.449 x10¹⁸ s⁻¹ or 5.449 x 10¹⁸ Hz