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Calculate the ph and poh of a 0.0032 M solution of nitric acid NHO3

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Answer:

HNO3 ->NO3²- + H+

Concentration of H+ ions= 0.0032M

pH = - log[ H+]

= - log (0.0032)

= 2.49

pH + pOH = 14

pOH = 14 - pH

= 14 - 2.49

= 11.51

pH = 2.49 and pOH = 11.51

Hope this helps.

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