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What is the value of i^n if the remember of n/4 is 2

1 Answer

2 votes

Answer: 1

Explanation:

If n/4 = 2, then n = 8


i^8 = i*i*i*i*i*i*i*i\\i*i=-1\\i^8=(-1)(-1)(-1)(-1) = 1*1 = 1

User Konrad Kokosa
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