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Find the equation of a line perpendicular to 2x-4y=1 that contains the point (-4, -2).

User JangoCG
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1 Answer

1 vote

Answer:

y = -2x - 10

Explanation:

1. rearrange to find the gradient.

the gradient of the original equation is 1/2 hence why a line PERPENDICULAR to that equation would have a gradient of -2.

2. substitute into y - y1 = m (x - x1)

y - (-2) = -2 (x - (-4))

y = -2x - 10

User CMTV
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