Question

image In the figure, is the segment bisector of AB such that AP = 15x – 11 and PB = 9x + 25. Find the value of x. Question 5 options: A) 6 B) 5 C) 7∕3 D) 10

Answer 1

x=6

Explanation:

15x-11=9x+25

15x-9x=25+11

6x=36

x=6

Answer 2

`x =6`

Explanation:

Given

Bisected Sector AB;

AP = 15x - 11

PB = 9x + 25

Required

Find x

When a sector is bisected, it means the sector is divided equally into two;

Hence
`AP = PB`

This gives

`15x - 11 = 9x + 25`

Add 11 to both sides

`15x - 11 + 11 = 9x + 25 + 11`

`15x = 9x + 25 + 11`

`15x = 9x + 36`

Subtract 9x from both sides

`15x - 9x = 9x + 36 - 9x`

`15x - 9x = 9x - 9x + 36`

`6x = 36`

Divide through by 6

`(6x)/(6) = (36)/(6)`

`x = (36)/(6)`

`x =6`

Hence, the value of x is 6