Question

what are the possible values of x in 8x^2+4=-1 a. 2+-iroot/3 b. -1+-i/6 c.-1+-i/4 d.1+-i/4 e. 1+-i root 2/4

Answer 1

x = ± i sqrt(5/8)

Explanation:

8x^2+4=-1

Subtract 4 from each side

8x^2+4-4=-1-4

8x^2 = -5

Divide by 8

8/8x^2=-5/8

x^2 = -5/8

Take the square root of each side

sqrt(x^2) = ±sqrt(-5/8)

x = ±sqrt(-5/8)

x = ±sqrt(5/8) sqrt(-1)

x = ± i sqrt(5/8)