Answer:
The answer is 3.87 J/g°C
Step-by-step explanation:
Here is the equation we are going to use:
![C=(q)/(mT)](https://img.qammunity.org/2021/formulas/chemistry/high-school/grfyaugessyzwjms0ewge8rp1uf7gx0b2s.png)
C= specfic heat in J/g°C
q = heat in joules (J)
m = mass in grams (g)
T = change in temperature
Here is what is given:
q = 849 J
m = 95.4 g
T = 48.0 - 25.0 = 23°C
Find:
Specific heat capacity in J/g
The first thing we are going to do is plug everything into the equation:
![C = (849J)/((9.54g)(23degreesC))](https://img.qammunity.org/2021/formulas/chemistry/high-school/806ijgsgnw8l965hm05phfkbjd2hry14s9.png)
Then we are going to solve for C
![C = (849J)/(219.42gC) = 3.87 J/gCelsius](https://img.qammunity.org/2021/formulas/chemistry/high-school/mnlse48qfmb97taxggaulm715k39oulujx.png)
Hope this helps!