Question

Aramis showed the division of 6p2 + 9p + 3 by 3p. A + 3 + B What are the values of A and B? A = 2p and B = p A = 3p and B = p A = and B = A = 2p and B =

Answer 1

D) A = 2p and B = 1/p

Explanation:

Answer 2

D) A = 2p and B = 1/p

Explanation:

To divide this,

we first see how many times 3p will go into 6p².

`(6p^2)/(3p) = 2p`

It will go in 2p times; this goes up top of the problem.

Multiplying back through, we have

`2p*3p = 6p^2`

Subtracting this from the first term under the box, we have

`6p^2-6p^2= 0.`

This cancels. Bring down the next term, 9p.

See how many times 3p goes into 9p =
`(9p)/(3p)=3`

it goes in 3 times. This goes up top, beside the 2p. We separate them with a +, since the 3 is positive.

Multiplying back through, we have 3(3p) = 9p.

Subtract this from the line above; 9p-9p = 0.

Bring down the last term, 3.

Since this is not 0, this is the remainder.

This gives us

2p + 3 R 3;

writing this as a rational expression, we have

`2p + 3 + (3)/(3p)`

The remainder term,
`(3)/(3p)`, will simplify to 1/1p or 1/p;

this gives us

`2p + 3 + (1)/(p)`

Therefore, the answer is A = 2p and B = 1/p