Question

The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the change in temperature per hour?

Answer 1

Negative StartFraction 7 over 2 EndFraction times StartFraction 49 over 4 EndFraction

Explanation:

A

Answer 2

The expression used to find the change in temperature per hour is Algebraic expression

Thus per hour; the temperature falls at the rate of
`- 3(1)/(2)^0`

Explanation:

A temperature falls from 0 to
`- 12(1)/(4)` in
`3(1)/(2) \ hours`

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is
`- 12(1)/(4)`

The change in temperature is
`\Delta T = T_2 - T_1`

`\Delta T = -12(1)/(4) -0`

`\Delta T = -12.25`

Thus;

-12.25 ° = 3.5 hours

To find the change in x° per hour; we have;

x° = 1 hour

The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

`(-12.25^0*1 )/(3.5)=( x^0 *3.5)/(3.5)`

x° = - 3.5

x° =
`- 3(1)/(2)`

Thus per hour; the temperature falls at the rate of
`- 3(1)/(2)^0`