Question

The given line passes through the points (-4, -3) and (4.

1)
What is the equation, in point-slope form of the line that is
perpendicular to the given line and passes through the
point (-4, 3)?
V-3 -2(x+4)
3-
2-
+
Oy-3 =-{(x+4)
Ov-3 = {(x + 4)
-2
y-3 =2(x + 4)
-3
(-3)

Answer 1

9514 1404 393

Answer:

y -3 = -2(x +4)

Explanation:

The slope of the given line is ...

m = (y2 -y1)/(x2 -x1)

m = (1 -(-3))/(4 -(-4)) = 4/8 = 1/2

The perpendicular line will have slope -1/(1/2) = -2.

__

The point-slope equation of the line with slope m through point (h, k) is ...

y -k = m(x -h)

For point (-4, 3) and slope -2, the equation is ...

y -3 = -2(x +4)