Question

F(n) = 4(n-1) + 7

fine the first three(3) terms in the sequence show all work​

Answer 1

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Answer 2

f(n) = 4(n-1) + 7

First term

f(1) = 4(1-1) +7 = 0 + 7 = 7

Second term

f(2) = 4(2-1) + 7

= 4(1) + 7 = 4 + 7 =11

Third term

f(3) = 4(3-1) + 7

= 4(2) + 7

= 8 + 7 = 15

Therefore the first three terms of the sequence are 7, 11 and 15.

Hope this helps