Answer:
Step-by-step explanation:
TT ×tt
I
Tt Tt Tt Tt
Where Tt Tt Tt TT are the genotype for the first filial generation.
To generate the 2nd filial generation, we self the 1st generation.
Tt × Tt
I
TT Tt Tt tt
We have TT Tt Tt tt as the second filial generation.
If a man and a woman both have Ee the probability that the child will have normal finger is 1/4
Ee × Ee
I
EE Ee Ee ee
Where EE, Ee is brachydactly and ee is normal finger.
When a man with normal eye is crossed with a man with beeturia the probability of having a child with beeturia 2/4
Bb × bb
I
Bb bb Bb bb
Where BB Bb is normal eye and bb is beeturia
When a man with colored eye lid HH is crossed with normal eyes lid hh the probability of having a child with color eyes lid is 1
HH × hh
I
Hh Hh Hh Hh
Where Hh represent normal eyes lid